- "Challenged" - - Pokemon Unite Player


Name:
- -
Date of Birth:
<unknown>
Australia
Australia
World Ranking:
N/A
Country Ranking:
#662

Total Prize Money Earned:
$4,833.33 From 6 Tournaments
Alternate IDs:
Challenged




Earnings By Year

Total ResultsOnline ResultsOffline/LAN Results
2024$1,500.00431.03%|$1,500.00431.03%|$0.0000.00%
2023$2,000.00141.38%|$2,000.00141.38%|$0.0000.00%
2022$1,333.33127.59%|$1,333.33127.59%|$0.0000.00%

Earnings By Game

Total ResultsOnline ResultsOffline/LAN Results
Pokemon Unite$4,833.336100.00%|$4,833.336100.00%|$0.0000.00%

Earnings By Team

Total ResultsOnline ResultsOffline/LAN Results
EXO Clan$2,000.00141.38%|$2,000.00141.38%|$0.0000.00%
Ground Zero Gaming$1,333.33127.59%|$1,333.33127.59%|$0.0000.00%
<independent>$1,500.00431.03%|$1,500.00431.03%|$0.0000.00%


Highest Prize Money Won

1.2023-06-112ndTeam-based Tournament » Pokemon UNITE Championship Series 2023 - OCE Championship$2,000.00Pokemon Unite
2.2022-06-193rdTeam-based Tournament » Pokemon UNITE Championship Series 2022 - OCE Championship$1,333.33Pokemon Unite
3.2024-05-124thTeam-based Tournament Pokemon UNITE Championship Series 2024 - OCE Championship$800.00Pokemon Unite
4.2024-02-101stTeam-based Tournament Pokemon UNITE Championship Series 2024 - OCE Aeos Qualifiers$300.00Pokemon Unite
5.2024-03-162ndTeam-based Tournament Pokemon UNITE Championship Series 2024 - OCE March Monthly$200.00Pokemon Unite
6.2024-12-152ndTeam-based Tournament Pokemon UNITE Championship Series 2025 - OCE December Monthly$200.00Pokemon Unite

Top Placements

Champion
Runner-up
3rd/Semis
1 Tournament
3 Tournaments
1 Tournament


Other Statistics

Largest Prize from a Single Tournament

Out of the 6 tournaments awarding cash prizes that Challenged had competed in, the largest amount was $2,000.00 from Pokemon UNITE Championship Series 2023 - OCE Championship on June 11, 2023. He placed 2nd, making up 41.38% of his total prize money won.



References


No external sources of information are cited for the player. See tournament references for sources.